Check adjacent java

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check adjacent java

Code Review Stack Exchange is a question and answer site for peer programmer code reviews. It only takes a minute to sign up. This little program was written for an assignment in a data structures and algorithms class. I'll just note the basic requirements:.

Given an inputted string, the program should check to see if it exists in a dictionary of correctly spelled words. If not, it should return a list of words that are obtainable by:.

The primary data structure is embodied in the Dictionary class, which is my implementation of a separately-chaining hash list, and the important algorithms are found in the charAppendedcharMissing and charsSwapped methods. Everything works as expected - I'm just looking for tips about anything that can be done more cleanly, efficiently or better aligned with best practices.

Many of the variable names lack meaning and are inconsistent. I cover some of them specifically below, but for example print is not a good choice for a list of suggestions--even though you intend to print them.

Instead, suggestions clearly identifies what the list holds. Learn to use JavaDoc for documenting public classes and methods. Not only is it nicer to read than one-liners, developing this habit early will demonstrate your goal to become a professional engineer if that's the case. You make a good effort at breaking up the methods and separating concerns, but I would take it a step further.

The methods that build alternate spellings should not be responsible for checking the dictionary. Instead, combine all misspellings into a single list and search the dictionary in one place. This also allows you to remove duplicates and avoid wasted lookups. I would also completely separate all output, possibly to a new UI class to allow reuse. You did pretty well here, but printSuggestions should receive the list of suggestions instead of calling makeSuggestions itself. If Dictionary implemented the Set interface, you could use the built-in intersection method to do the lookups for you.

This applies similarly to ArrayList : print. You use two different methods of concatenating strings when building suggestions: an implicit StringBuilder and String. Both are fine in different circumstances though I confess that I've never used the latterbut make sure you combine all the concatenations in one statement.Sign in to comment. Sign in to answer this question. Unable to complete the action because of changes made to the page. Reload the page to see its updated state.

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The dark mode beta is finally here. Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. How can I do this? I have a rough idea of how to check rows and columns very rough; no code, just thoughts but I'm at a loss for checking the diagonal. Edit: one other situation I'm thinking about: how can I check arbitrary positions?

Right now, I'm only considering occurrences starting at 0,0but what if there's a string of 3 from, say, 2,3 to 2,6? How could I keep track of multiple occurrences? The simplest though not the most efficient as it may backtrack solution that comes to mind is to write a recursive function, like the following psuedocode. This routine would, given a coordinate x,y, return the of symbols around it in a 'blob'.

Note: This also means grouping of symbols such as 3 in a row, with 1 next to it in a column below. Remember to do bounds checking so you do not check matrix[-1][-1] or anything. You're going to be running a lot of nested loops i would imagine. Don't forget all the diagonals. First, don't trust your "Thought". Write the real code out to make sure you can make the row and column checking works. Loop through the checker board.

Assume the top-left is [0,0], then go right [0,1], [0,2] Then go to next line. Finish until you hit the bottom right box. For each box, check if there is k occurrence 1. Edit: as the author seems don't really understand what I am talking about What you have to do is to check. Learn more. How to detect adjacent entries in an array? Ask Question. Asked 7 years, 6 months ago.

Active 7 years, 6 months ago. Viewed 6k times.

Find all reachable nodes from every node present in a given set

Anything else you need? If you're having any pain on a specific problem, feel encouraged to edit your question addressing such - depending on the nature of the problem, providing code as necessary. You should write the code for checking rows first.

Get it working. Then move on to columns. Once you get both of those working, diagonals should be fairly obvious.By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

The dark mode beta is finally here. Change your preferences any time. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. I've created a 12x12 grid, and within this grid I have created 'infected' tiles, when one infected tile is surrounded by other infected tiles, the surrounded cell becomes a diseased tile. I was wondering if there was a nice way of checking adjacent, in bounds cells for their value?

You might consider padding your array with a boundary one cell deep around each edge, so your 12x12 would become a 14x Make each cell in the boundary infected.

You can then loop over the interior cells ie rowscols without having to check that the cell is at the edge all the time. I believe a better option is to define a helper array that defines the valid neighbors and iterate using it. Advantage of my approach is that it makes it very easy to change which are the valid neighbors say you want to have 8 neighbors allowing to go by diagonal instead of only 4 :. Learn more.

Remove Duplicates from sorted Array

Multi-dimensional array, how can I check all adjacent tiles that are IN bounds to certain cells? Ask Question. Asked 6 years, 4 months ago. Active 4 years, 1 month ago. Viewed 4k times. Roman C LeonH LeonH 1 1 gold badge 12 12 silver badges 41 41 bronze badges. You've done it the other way around. Yeah, I realised after I'd started.

It seemed natural to have i then j, oh well. I know which is which. Active Oldest Votes. What will the value be of these booleans if the cell is in fact, out of bounds? Okay, I can work with this.Given an unsorted array of numbers, write a function that returns true if array consists of consecutive numbers. Method 1 Use Sorting 1 Sort all the elements. If the difference between current element and next element is anything other than 1, then return false.

If all differences are 1, then return true. Method 2 Use visited array The idea is to check for following two conditions. If following two conditions are true, then return true. To check if all elements are distinct, we can create a visited[] array of size n.

check adjacent java

We can map the ith element of input array arr[] to visited array by using arr[i] — min as index in visited[]. Method 3 Mark visited array elements as negative This method is O n time complexity and O 1 extra space, but it changes the original array and it works only if all numbers are positive. We can get the original array by adding an extra step though.

It is an extension of method 2 and it has the same two steps. In this method, the implementation of step 2 differs from method 2. Instead of creating a new array, we modify the input array arr[] to keep track of visited elements. If we see a negative value again then there is repetition. Note that this method might not work for negative numbers. Writing code in comment? Please use ide. If elements are consecutive, then returns true, else returns.

Note that, calloc is used here so that all values are initialized. Helper functions to get Minimum and. The function checks if the array elements. If elements are consecutive. Create a temp array to hold visited. Note that, calloc.

check adjacent java

If we see an element again. If visited first time, then mark. If all elements occur once. This code is contributed by mohit kumar. Write "Array elements are". Helper functions to get minimum and. The function checks if the array.Given an undirected graph and a set of vertices, find all reachable nodes from every vertex present in the given set. Consider below undirected graph with 2 disconnected components.

Method 1 Simple One straight forward solution is to do a BFS traversal for every node present in the set and then find all the reachable nodes. Please note that we need to call BFS as a separate call for every node without using the visited array of previous traversals because a same vertex may need to be printed multiple times.

Method 2 Efficient Since the given graph is undirected, all vertices that belong to same component have same set of reachable nodes. So we keep track of vertex and component mappings.

Every component in the graph is assigned a number and every vertex in this component is assigned this number. We use the visit array for this purpose, the array which is used to keep track of visited vertices in BFS. To store the reachable nodes, use a map m with key as component number and value as a vector which stores all the reachable nodes.

To find reachable nodes for a node u return m[visit[u]] Look at the pseudo code below in order to understand how to assign component numbers. For the graph shown in the example the visit array would be. For the nodes 1, 2, 3 and 4 the component number is 1. For nodes 5, 6 and 7 the component number is 2. This article is contributed by Chirag Agarwal. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.

See your article appearing on the GeeksforGeeks main page and help other Geeks. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

Writing code in comment? Please use ide. Add and Remove vertex in Adjacency Matrix representation of Graph Program to print all the non-reachable nodes Using BFS Maximal Clique Problem Recursive Solution Minimum cost to traverse from one index to another in the String Check if given path between two nodes of a graph represents a shortest paths Minimum number of colors required to color a graph Maximum number of edges that N-vertex graph can have such that graph is Triangle free Mantel's Theorem.

Graph::Graph int V. If a adjacent has not been visited. BFS componentNum, u, visited. Graph g V. Recommended Posts: Minimum edges to be added in a directed graph so that any node can be reachable from a given node Program to print all the non-reachable nodes Using BFS Count the number of non-reachable nodes Kth largest node among all directly connected nodes to the given node in an undirected graph XOR of all the nodes in the sub-tree of the given node Maximum number of nodes which can be reached from each node in a graph.

Minimum cost path from source node to destination node via an intermediate node Find maximum among all right nodes in Binary Tree Find the product of last N nodes of the given Linked List Find count of pair of nodes at even distance Program to find average of all nodes in a Linked List Find the shortest distance between any pair of two different good nodes Find the common nodes in two singly linked list Find count of common nodes in two Doubly Linked Lists Find the path from root to the given nodes of a tree for multiple queries.

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Check whether given three numbers are adjacent primes

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check adjacent java

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